We know that when the input is the simplest unit impulse d[n], the output response will be the impulse response. Therefore,
replacing input x[n] by d[n] and response y[n] by h[n], the equation is still holding and has become special:
h[n]=3 d[n] + d[n-1] + 4 d[n-2]
It is easy to evaluate the impulse response by letting n=-1, 0,1,2,3,…
When n=-1, h[-1]=0
When n=0, h[0]= 3 d[0] +d[-1] + 4 d[-2]=3
When n=1, h[1]= 1,
When n=2, h[2]= 4,